Bonus
The Lee–Huang–Yang formula gives the energy of a gas named after this physicist. For 10 points each:
[10e] Name this Indian physicist who gives his name to particles with integer spin.
ANSWER: Satyendra Nath Bose [accept Bose gases or bosons]
[10m] When the Bose gas forms a Bose–Einstein condensate, it can be modeled using the Gross–Pitaevskii equation, which is a Schrödinger equation with this property. Superposition of solutions in quantum mechanics is possible because the standard Schrödinger equation has the [emphasize] opposite of this property.
ANSWER: nonlinear [accept nonlinearity or nonlinear Schrödinger equation]
[10h] The nonlinearity in the Gross–Pitaevskii equation is formally defined by performing this operation on the delta distribution. This operation is performed on the free Schrödinger kernel and the initial condition to solve the linear Schrödinger equation.
ANSWER: convolution [or convolving]
<Physics>
Answerlines and category may not exactly match the version played at all sites
Conversion
Team | Opponent | Part 1 | Part 2 | Part 3 | Total | Parts |
---|---|---|---|---|---|---|
British Columbia | Arizona State | 10 | 0 | 0 | 10 | E |
Columbia A | Toronto A | 10 | 0 | 0 | 10 | E |
Columbia B | Ohio State | 10 | 10 | 0 | 20 | EM |
Georgia Tech | Toronto B | 10 | 0 | 0 | 10 | E |
Illinois A | Waterloo A | 10 | 0 | 0 | 10 | E |
Indiana | Chicago A | 10 | 10 | 10 | 30 | EMH |
Iowa State | Harvard | 10 | 0 | 10 | 20 | EH |
Johns Hopkins | Texas | 10 | 0 | 10 | 20 | EH |
MIT | Minnesota | 10 | 10 | 10 | 30 | EMH |
Maryland | RIT | 10 | 10 | 10 | 30 | EMH |
Michigan | Illinois B | 10 | 0 | 0 | 10 | E |
North Carolina B | Winona State | 0 | 0 | 0 | 0 | |
Ottawa | NYU | 10 | 10 | 0 | 20 | EM |
Penn State | Georgia State | 10 | 10 | 0 | 20 | EM |
Rutgers | Northwestern | 10 | 0 | 0 | 10 | E |
Toronto C | Cornell A | 10 | 0 | 0 | 10 | E |
UC Berkeley A | Stanford | 10 | 0 | 0 | 10 | E |
Vanderbilt | Cornell B | 0 | 0 | 0 | 0 | |
Virginia | UCF | 10 | 0 | 0 | 10 | E |
Virginia Tech | Chicago B | 10 | 0 | 10 | 20 | EH |
WUSTL A | North Carolina A | 10 | 10 | 10 | 30 | EMH |
WUSTL B | Florida | 10 | 10 | 0 | 20 | EM |
Waterloo B | UC Berkeley B | 10 | 0 | 0 | 10 | E |
Yale | LSE | 10 | 0 | 0 | 10 | E |
Summary
Tournament | Exact Match? | Heard | PPB | Easy % | Medium % | Hard % |
---|---|---|---|---|---|---|
2025 ACF Nationals | Yes | 24 | 15.42 | 92% | 33% | 29% |